4x/(x-4)=2+(10x^2)/(x-4)

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Solution for 4x/(x-4)=2+(10x^2)/(x-4) equation:


D( x )

x-4 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

(4*x)/(x-4) = (10*x^2)/(x-4)+2 // - (10*x^2)/(x-4)+2

(4*x)/(x-4)-((10*x^2)/(x-4))-2 = 0

(4*x)/(x-4)-10*x^2*(x-4)^-1-2 = 0

(4*x)/(x-4)+(-10*x^2)/(x-4)-2 = 0

(4*x)/(x-4)+(-10*x^2)/(x-4)+(-2*(x-4))/(x-4) = 0

4*x-2*(x-4)-10*x^2 = 0

4*x-10*x^2-2*x+8 = 0

2*x-10*x^2+8 = 0

2*x-10*x^2+8 = 0

2*(x-5*x^2+4) = 0

x-5*x^2+4 = 0

DELTA = 1^2-(-5*4*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)-1)/(-5*2) or x = (-81^(1/2)-1)/(-5*2)

x = -4/5 or x = 1

2*(x+4/5)*(x-1) = 0

(2*(x+4/5)*(x-1))/(x-4) = 0

(2*(x+4/5)*(x-1))/(x-4) = 0 // * x-4

2*(x+4/5)*(x-1) = 0

( x+4/5 )

x+4/5 = 0 // - 4/5

x = -4/5

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -4/5, 1 }

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